Proving the Identity: cot x + tan x = sec x csc x

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SUMMARY

The identity cot x + tan x = sec x csc x can be proven using fundamental trigonometric identities. Specifically, tan x is defined as sin x / cos x and cot x as cos x / sin x. By combining these definitions, the left-hand side simplifies to (cos^2 x + sin^2 x) / (sin x cos x), which equals 1 / (sin x cos x). This matches the right-hand side, sec x csc x, confirming the identity.

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Johnny Blade
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I need to prove algebraically this and I'm having trouble with it.

cot x + tan x = sec x csc x

Can anyone help me?
 
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What is tan x in terms of sin x and cos x? And cot x?
 
Ahh... I see.

cos^2 x + sin^2 x
------------------ = MD
sin x cos x

1
---------- = MD
sin x cos x

Then

sec x csc x= sec x csc x CQFD

I always see those problem and try to complicate things. Thanks for your help.
 

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