Proving the identity of the field

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SUMMARY

The discussion centers on proving that the set S = {s in R such that s ≠ 1} forms a field under the circle operation defined as a * b = a + b - ab. The main challenge is verifying the existence of the identity element for the multiplicative operation. Participants clarify that the identity element is not 0, but rather can be determined by solving the equation a + e + ae = a for e, leading to the conclusion that e = 0 is incorrect in this context.

PREREQUISITES
  • Understanding of group theory and abelian groups
  • Familiarity with field axioms and operations
  • Knowledge of the specific circle operation defined as a * b = a + b - ab
  • Ability to solve algebraic equations involving identities
NEXT STEPS
  • Study the properties of abelian groups and their identities
  • Learn about field axioms and how they apply to different operations
  • Investigate the implications of the circle operation in abstract algebra
  • Explore examples of fields and their multiplicative identities
USEFUL FOR

Mathematics students, particularly those studying abstract algebra, and educators looking to deepen their understanding of field theory and group operations.

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Homework Statement


If S = {s in R such that s=/=1} is an abelian group under circle operation (Circle Operation a*b = a + b -ab for a, b in R) then R is a field

Homework Equations


The verification of the field axioms

The Attempt at a Solution


The field axiom that I'm struggling to verify is the existence of the identity for the multiplicative operation since s=/=1. I'm wondering if someone can help me resolve this.

Thanks
 
Physics news on Phys.org
Isn't the identity 0? Why do you think it's not?
 
If aob= a+ b- ab Then the identity, e, must satisfy a+ e+ ae= a for all a. Solve that for e.
 

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