Proving the limit of sinx/x as x approaches 0 equals 1

  • I
  • Thread starter Terrell
  • Start date
  • Tags
    Limit
  • #1
317
26
this is a geometric proof from James Stewart's calculus textbook page 192. I'm confused in the sequence of inequalities as part of the proof...
theta = arcAB < AB + EB ==> arcAB < AE + ED. How did EB turned into ED?
please check the picture I've uploaded with this post
 

Attachments

  • image.jpeg
    image.jpeg
    38.6 KB · Views: 2,108

Answers and Replies

  • #2
In the first diagram, it' easy to see that ##\left|EB\right| < \left|ED\right|##, so what you ask follows. Then there are just substitutions.
 
  • #3
Point D was described in the first half of the proof. It should be clear that |ED| > |EB|.
The benefit of doing the substitution is that you can reduce the expression to one involving straight segments related to theta by trigonometric functions.
##\tan \theta = \frac{|AD|}{|OA|}##
 

Suggested for: Proving the limit of sinx/x as x approaches 0 equals 1

Replies
5
Views
792
Replies
3
Views
446
Replies
6
Views
904
Replies
16
Views
836
Replies
14
Views
375
Replies
29
Views
1K
Replies
3
Views
602
Replies
1
Views
511
Replies
3
Views
937
Back
Top