Proving the Sum of Vector Areas in a Tetrahedron is Zero

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SUMMARY

The discussion centers on proving that the sum of four vectors, each representing the area of a face of a tetrahedron and oriented outward, equals zero. The vectors are derived from the edges of the tetrahedron, represented by vectors A, B, and C. Additionally, the conversation explores a similar proof for a planar triangle, where the side vectors also sum to zero when oriented outward. The analogy between the tetrahedron and triangle is established through geometric transformations.

PREREQUISITES
  • Understanding of vector mathematics and operations
  • Familiarity with tetrahedron geometry
  • Knowledge of planar geometry and triangle properties
  • Basic skills in vector representation and manipulation
NEXT STEPS
  • Study vector addition and its geometric interpretations
  • Learn about the properties of tetrahedrons and their face areas
  • Explore proofs involving planar triangles and vector orientations
  • Investigate applications of vector calculus in geometry
USEFUL FOR

Students and educators in mathematics, particularly those focusing on geometry and vector calculus, as well as anyone interested in geometric proofs and their applications.

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Homework Statement


Four vectors are erected perpendicular to the four faces of a general tetrahedron. Each vector is pointing outwards and has a length equal to the area of the face. Show that the sum of these four vectors is zero.

Homework Equations



The Attempt at a Solution


Let A, B and C be vectors representing the three edges starting from a fixed vertex. Then, express each of the four vectors in terms of A, B and C.
 
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I figured out how to do the problem.

But there's another part to the problem: Formulate and prove the analogous statement for a plane triangle.

What is meant by a "planar triangle"?
 


i think it probably just means any normal triangle (normal in the sense that it is contained within in a plane in R^3, so planar)

can you show it for such? where I'm guessing the analogy is area to length
 


Put your triangle in the xy plane; label the vertices A,B,C clockwise. Make vectors of the sides going from A to B, B to C, C to A (i.e, \vec a = B - A etc.). Those side vectors add to the zero vector. Now rotate the triangle 90 degrees counterclockwise and they become perpendicular to the original sides pointing outward and the right length. Presto!
 


I am trying to solve this same problem. Would the person who asked the question and said he/she figured it out please tell me how its done? Unfortunately, it is just not clicking with me. Thank you.
 


Could you explain how you solved this?
 

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