Proving the Theorem: A, B, C, and D Vectors | Step-by-Step Guide

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SUMMARY

The discussion centers on proving the vector theorem (A×B)·(C×D) = (A·C)(B·D) - (A·D)(B·C) using vector operations. Key equations include the cross product A×B = ABsin(θ) and the dot product A·B = ABcos(θ). Participants suggest utilizing coordinate notation for vectors, specifically A = and B = , to simplify the proof. The conversation emphasizes the importance of understanding vector notation and operations to effectively tackle the theorem.

PREREQUISITES
  • Understanding of vector operations, specifically cross products and dot products.
  • Familiarity with coordinate notation for vectors.
  • Knowledge of trigonometric functions, particularly sine and cosine.
  • Ability to manipulate algebraic expressions involving vectors.
NEXT STEPS
  • Study the properties of vector cross products and their geometric interpretations.
  • Learn about vector dot products and their applications in physics.
  • Explore coordinate systems and their role in vector calculations.
  • Review proofs of vector identities to strengthen understanding of vector relationships.
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Students studying vector calculus, mathematicians, and anyone interested in mastering vector operations and proofs in physics or engineering contexts.

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Homework Statement



How can I prove this theorem? A, B, C and D are vectors.

(A\timesB).(C\timesD)=(A.C)(B.D)-(A.D)(B.C)

Homework Equations



A\timesB=ABsin(\theta) and A.B=ABcos(\theta)

The Attempt at a Solution



Please help me solve it.
 
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There's one more relevant equation. As a hint, think of AxB as an additional vector V.
 
VeeEight said:
This can get messy, but have you considered the coordinate notation, that is for vectors A = <a1, a2, a3>, B = <b1, b2, b3>, A x B = <a2b3 - a3b2, a3b1 - a1b3, a1b2 - a2b1>
(http://en.wikipedia.org/wiki/Cross_product#Matrix_notation)

yeah I'm sure that this solves the problem, and it seems obvious, so thank u very much, but do u know an easier way or a cleaner (lol) way to prove it.
 

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