Show: Vectors e.g.(a,b,1) do not form vector space.

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SUMMARY

The discussion confirms that vectors of the form (a,b,1) do not constitute a vector space due to the failure to include the null vector (0,0,0) and the inability to maintain closure under vector addition. Specifically, the sum of two vectors (c,d,1) and (e,f,1) results in (c+e, d+f, 2), which does not conform to the original form (a,b,1). Therefore, these vectors do not satisfy the necessary conditions for a vector space.

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Homework Statement


upload_2018-8-12_19-29-5.png


Homework Equations


definition of null vector,
upload_2018-8-12_19-40-16.png
[/B]

The Attempt at a Solution


null vector : ## |0 \rangle = (0,0,0) ##
inverse of (a,b,c) = ( - a, -b, -c)
vector sum of the two vectors of the same form e.g. (c,d,1) + ( e,f,1) = ( c+e, d+f, 2) does not have the same form. So, the vectors of the form ( a,b,1) do not form a vector space.

Is this correct?
 

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Last edited:
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Yes, or even easier ##(0,0,0) \notin \{\,(a,b,1)\,\}##.
 
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fresh_42 said:
Yes, or even easier ##(0,0,0) \notin \{\,(a,b,1)\,\}##.

Thanks for it.
 

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