Proving Vector A and d\vec{}A/dt Are Perpendicular With Constant Magnitude

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Homework Help Overview

The problem involves proving that a vector \(\vec{A}\) with constant magnitude is perpendicular to its time derivative \(d\vec{A}/dt\), under the condition that \(d\vec{A}/dt \neq 0\). The context suggests a connection to circular motion due to the constant magnitude of the vector.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • One participant suggests visualizing the problem through circular motion, indicating that only the position of the vector changes while maintaining constant magnitude. Another participant expresses confusion and requests direct assistance, while a third participant emphasizes the importance of following forum rules and encourages self-work.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been provided in the form of hints, but there is no explicit consensus or resolution yet.

Contextual Notes

Participants are reminded of forum rules regarding homework help, emphasizing the expectation that they engage with the problem rather than seek complete solutions.

jawwadaziz
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please help me(a vector problem)

Homework Statement



i m very confuse about this assignment. please help me how to prove.

If \vec{}A has constant magnitude show that \vec{}A and d\vec{}A/dt are perpendicular provided that d\vec{}A/dt \neq0

also give one physical example of this problem.

please help me in this problem.

thnx.


Homework Equations





The Attempt at a Solution

 
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This can be thought of as a circular motion problem with constant radius. Since the radius vector has a constant magnitude (constant radius), then only the position of the vector changes with time. Draw two vectors with magnitue A, one displaced an amount delta theta from the other. Find the vector difference which will be delta A, then take the limit of delta A divided by delta theta as delta theta goes to zero.
 


i didnt got u !

Hey Chris buddy can u pleasez solve it for me pleasez..

thnx in advance.
 


jawwadaziz said:
i didnt got u !

Hey Chris buddy can u pleasez solve it for me pleasez..

thnx in advance.

No, we will not solve this for you. You have been given a great hint, and now the rest is up to you.

Please re-read the Rules link at the top of the page, especially the part about how you must do the bulk of the work on homework/coursework problems.

Show your work, and if you have a specific question, we can offer hints and tutorial help. We do not do your homework for you.
 


ooops sorry !

I didnt knew the rules..
it won't happen next tym.
 


The magnitude of A squared is A.A (dot product). Is that a help?
 

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