Proving Work is Same for All Paths of a Conservative Force

Click For Summary

Homework Help Overview

The discussion revolves around the concept of conservative forces, specifically focusing on gravity and the assertion that the work done by such forces is independent of the path taken. Participants are exploring how to demonstrate that the work done by a conservative force is the same for all paths.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning how to prove that the work done by gravity is the same for all paths. Some suggest defining the force as the gradient of a potential, while others explore the mathematical representation of the force in relation to gravity.

Discussion Status

The discussion is ongoing, with participants offering various perspectives on the nature of conservative forces and the specific characteristics of gravitational force. There is an exploration of different interpretations regarding the relationship between force and potential energy, but no consensus has been reached.

Contextual Notes

Participants are considering the implications of gravity acting along a radius vector and discussing the nuances of gravitational force as it varies with distance from the Earth. There is an acknowledgment of the complexity of defining forces in this context.

Dustinsfl
Messages
2,217
Reaction score
5
So for a force to be conservative it can only depend on position and the work as to be the same for all paths.

The force mass time gravity is conservative but how do I show the all paths are the same?
 
Physics news on Phys.org
Dustinsfl said:
So for a force to be conservative it can only depend on position and the work as to be the same for all paths.

The force mass time gravity is conservative but how do I show the all paths are the same?

Why don't you just show the force can be defined as the gradient of a potential? Guess the potential if you have to.
 
Since gravity is acting along the radius to the center of earth, then would ##\mathbf{F}(\mathbf{r}) = -m\mathbf{r}##?
 
Dustinsfl said:
Since gravity is acting along the radius to the center of earth, then would ##\mathbf{F}(\mathbf{r}) = -m\mathbf{r}##?

That is a conservative force, but I don't think Newton would agree it has much to do with gravity. What are you thinking?
 
Dick said:
That is a conservative force, but I don't think Newton would agree it has much to do with gravity. What are you thinking?

I wrote why I put that.

I said since gravity is acting along the raidus vector to the center of Earth then could I wrtie F in such a manner.
 
Dustinsfl said:
I wrote why I put that.

I said since gravity is acting along the raidus vector to the center of Earth then could I wrtie F in such a manner.

There are a LOT of possible forces that would act along a radius vector to the center of the earth. Gravity is a special one. Not that it even matters for showing it's conservative, but don't you know more about gravity than that? -mr increases in magnitude as you move away from the earth. That's not gravity.
 
Last edited:

Similar threads

Replies
9
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
4
Views
2K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
15
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K