Ψ=f(r)exp[-i(Et-pz+Φ/2)] a Q.M. wave function?

  • B
  • Thread starter Spinnor
  • Start date
  • #1
Spinnor
Gold Member
2,123
318

Main Question or Discussion Point

In cylindrical coordinates could Ψ=f(r)exp[-i(Et-pz+Φ/2)] be a valid quantum mechanical wave-function for the right boundary conditions and with the right choice of f(r)?

Thanks!
 

Answers and Replies

  • #2
88
46
Your suggestion doesn't appear to be normalizable if you allow ##z\in(-\infty,\infty)##. Consider ##\int |\Psi|^2 \mathrm{d}zr\mathrm{d}r\mathrm{d}\theta##. You are forced to do the integral ##\int\limits_{-\infty}^{\infty}1\mathrm{d}z##.

EDIT: I suppose the answer to your exact question is that, yes, it could be a wavefunction with an appropriate restriction on the domain in the z-direction.
 
Last edited:
  • #3
blue_leaf77
Science Advisor
Homework Helper
2,629
784
In cylindrical coordinates could Ψ=f(r)exp[-i(Et-pz+Φ/2)] be a valid quantum mechanical wave-function for the right boundary conditions and with the right choice of f(r)?

Thanks!
Judging from the expression of the wavefunction, there can be two possibilities about the condition of the potential along the z-direction:1) The potential is constant along this direction, for which reason ##p## is continuous or 2) there is an infinite square well confining the space along z direction, in this case ##p## must be discrete.
Either way, the function you have there is bounded at infinities and therefore it can act as a basis function, despite being not normalizable for the case of continuous ##p##, for a physically realizable state.

EDIT: The only possible potential form in the z direction in this case is a constant potential. Therefore ##p## must be continuous.
 
Last edited:
  • #4
Spinnor
Gold Member
2,123
318
Thanks for pointing out things I should of worried about. My main concern was the angular coordinate Φ divided by two by which I was naively trying to get something like spin 1/2 angular momentum.

Thanks!
 
  • #5
blue_leaf77
Science Advisor
Homework Helper
2,629
784
Spin? That was not mentioned in your original post.
 
  • #6
Spinnor
Gold Member
2,123
318
Spin? That was not mentioned in your original post.
Yes, but but my function depends on angular coordinates (there is angular momentum?). My function only returns to itself after a 4π rotation and I'm not sure that is acceptable.

Thanks!
 
  • #7
blue_leaf77
Science Advisor
Homework Helper
2,629
784
My function only returns to itself after a 4π rotation and I'm not sure that is acceptable.
Rotation operator due to spin angular momentum can only rotate spin state, it does not act on spatial wavefunction.
 
  • #8
Spinnor
Gold Member
2,123
318
So two problems with my function above, Ψ=f(r)exp[-i(Et-pz+Φ/2)]. The first is the function is undefined along the cylindrical axis (though I guess I could set f(r) to zero there). I thought I could get away from that problem by using the function in some annular region where the azis was excluded.

The second more worrisome problem is the fact that the function only returns to itself after two complete rotations,

Ψ=f(r)exp[-i(Et-pz+Φ/2)] = Ψ=f(r)exp[-i(Et-pz+[Φ+4π]/2)]

What trouble do we get in if Ψ(r,z,Φ) ≠ Ψ(r,z,Φ+2π) but Ψ(r,z,Φ) = Ψ(r,z,Φ+4π)?

Thanks Blue_leaf for your help!
 

Related Threads on Ψ=f(r)exp[-i(Et-pz+Φ/2)] a Q.M. wave function?

Replies
3
Views
1K
Replies
31
Views
5K
Replies
3
Views
558
Replies
4
Views
2K
Replies
61
Views
3K
Replies
2
Views
1K
  • Last Post
Replies
1
Views
607
Replies
57
Views
6K
Replies
7
Views
674
Replies
1
Views
858
Top