Pulley question about a mass on a string

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SUMMARY

The discussion revolves around a physics problem involving a pulley system with a 0.40 m diameter wheel and a 0.50 kg mass. The object accelerates downward at 5.0 m/s², leading to the need to calculate the tension in the rope, torque on the pulley, angular acceleration, and moment of inertia. The correct tension in the rope is determined to be 2.4 N, contrary to the initial incorrect calculation of 2.5 N. This discrepancy arises from the need to account for the net force acting on the object, as the weight of the object exceeds the tension due to its acceleration.

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slain4ever
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Homework Statement



i'm having a lot of trouble with this question.


A pulley, consisting of a 0.40 m diameter wheel mounted on a horizontal frictionless axle, is firmly attached to the ceiling. A light rope wrapped around the pulley supports a 0.50 kg object, as shown in the diagram below. Any motion of the rope causes the pulley to turn, with no slipping between the rope and pulley. When released from rest, the object accelerates downward at 5.0 m/s2.

1) find the tension in the rope.
2) the torque on the pulley from the rope
3) the angular acceleration of the pulley
4) the moment of inertia of the pulley.


Homework Equations



F=T+ma = 0

The Attempt at a Solution



I'm stuck on the first part i keep getting 2.5N since the tension = ma it should be T=5m/s^2 * 0.5 kg but the answers say 2.4N and I can't figure out why. I am assuming it has something to do with the pulley but since it is frictionless i don't see how it adds tension.
 
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slain4ever said:
Relevant equations

F=T+ma = 0

The Attempt at a Solution



I'm stuck on the first part i keep getting 2.5N since the tension = ma it should be T=5m/s^2 * 0.5 kg but the answers say 2.4N and I can't figure out why. I am assuming it has something to do with the pulley but since it is frictionless i don't see how it adds tension.
Look at your relevant equation again,T does not = ma. Use your relevant equation by first identifying the value of F acting on the object.
 
f= ma
0.5 kg * 5 m/s^2
=2.5 N
 
looking at the forces acting on the object, its weight acts down and the tension acts up. Since the object is falling and accelerating down, the weight force must be greater than the tension force, thus, from Newton 2,
F_net = ma
mg -T =ma
Solve for T.
Note that tension forces always pull away from the objects on which they act, and that acceleration is always in the direction of the net force.
 

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