- #1

Mayzu

- 7

- 0

## Homework Statement

http://imgur.com/ymNWTOV

Image isn't working, here is the question:

http://imgur.com/ymNWTOV

## Homework Equations

F=ma

Weight force=mg

Frictional force=

**μ**

_{k}N## The Attempt at a Solution

So for part (a):[/B]

Force on 10kg block=mg=10x9.8=98N

This is equal to the tension force in the string, which is pulling the 5kg block right

Frictional force on the 5kg block (pulling it left):

F=

**μ**

_{k}N=0.4*(mg)

=0.4*9.8*5

=19.6N

Therefore the net force on the block is 98-19.6=78.4N

F=ma

Therefore accelaration(5kg block)=F/m=78.4/5

This gave me 15.68m/s

^{2}, while the answer was actually 5.23...

__Part b__

I have no clue how to do this part! Answer is 3.29J...