Pulling Horizontally: Force Problems - Help Needed

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SUMMARY

The discussion focuses on calculating the force required to move a block with a mass of 175.0 kg and a coefficient of static friction of 0.12. To initiate movement, the applied force must overcome the static friction, calculated as static friction force equals 0.12 multiplied by the normal force (N), which is the weight of the block. When a second identical block is added, and both are pulled with a force of 250.0 N, the acceleration can be determined using the equation: Net force equals applied force minus kinetic friction force, which is 0.10 multiplied by the combined weight of both blocks.

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Please Help! (Force Problems)

Pulling horizontally on a rope moves a block with a total mass of 175.0 kg. If the coefficient of static friction between the block and the ground/slope is 0.12, what force must be applied to the rope to start the sled moving? If a second identical block is tied to the first block, and both are pulled with a force of 250.0 N, what acceleration will both experience, if the coefficient of kinetic friction is 0.10? Please help! I do not really understand how to approach this problem because I am having understanding forces.
 
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Part one: what is the weight of your block?
 
First part
Limiting force will be static friction * N = static friction * mg
that you can easliy calculate
Second part
Net force in the direction of motion will be
250 -kinetic friction* (N1 + N2)
= 250 -0.10(m1g + m2g)
= (m1 + m2) a
if you know m 1 and m2 ...you can easily calculate acceleration.

enjoy
 

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