Pulse Height Of Pulse Amplifier

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Homework Help Overview

The discussion revolves around a problem related to pulse amplifiers, specifically focusing on calculating charge and current in a circuit. The problem is divided into two parts, with participants exploring the relationships between charge, current, and time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the equation Q=CV for part A and questions the approach for part B. Some participants suggest using Ohm's law to find current and discuss how to interpret the results in terms of charge over time.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on how to approach the calculations. There is a mix of interpretations regarding the conversion of current to charge, and multiple lines of reasoning are being explored without reaching a consensus.

Contextual Notes

There are indications of uncertainty regarding the definitions and conversions involved in the calculations, particularly in relation to the units of charge and current.

baltimorebest
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Homework Statement



I have attached the question as a photo. It contains two parts.

Homework Equations





The Attempt at a Solution



For part A, is it simply Q=CV where C is given and Q is the elementary charge times 10^6?


For B, I am not quite sure where to begin.

Any advice on both parts is appreciated. Thank you very much, in advance.
 

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Use Ohm's law to find the current, I.

I = ΔQ / Δt.

Find how much charge passes any point in the circuit in 1 microsecond.
 
Thanks for responding. Is my thinking for part A correct?

And for part B, I get a value of .05 A but how do I convert that to the needed result? Is .05 A in terms of seconds, and I have to divide by 10^-6?
 
What is the definition of an ampere?
 
Coulomb per second I believe. So would it just be that number over 10^-6?
 
baltimorebest said:
Coulomb per second I believe. So would it just be that number over 10^-6?

Coulombs per second times 10‒6 seconds gives Coulombs.
 
Ahh ok that's what I meant. Thanks. Are the rest of my thoughts correct?
 

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