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Python program to sort negative numbers and even numbers?

  1. Mar 30, 2015 #1
    1. The problem statement, all variables and given/known data
    I have to make a program that would end when entered a 0 and print out negative numbers and even numbers separately but what I have so far is not working.

    3. The attempt at a solution

    Code (Text):

    numbers = []
    negative_numbers = []

    while True:
        number = input("Enter a number: ")
        if number == "0":
            print ("A zero has been entered.")
            break
        for i in number:
            number = int(number)
            if i >= 0:
                numbers.append(i)
            else:
                negaitve_numbers.append(i)


    print ("Numbers: ", numbers)
    print ("Negative numbers: ", negative_numbers)
     
    Any suggestions?
     
  2. jcsd
  3. Mar 30, 2015 #2

    Mark44

    Staff: Mentor

    Here are several.
    1. Instead of numbers for one of your lists, I recommend calling it even_numbers, to be more suggestive of what you'll put in it.
    2. Instead of checking for number == "0" convert the input right away to an integer.
    Code (Python):
    entry = input("Enter a number")
    number = int(entry)
    After that, your logic looks like if number == 0:
    3. Don't use a for loop. Just continue on with more elif clauses. This code makes no sense to me:
    Code (Text):
    for i in number:
    4. To check whether a number is even, use the modulus operator %. The expression n % 2 evaluates to the remainder when n is divided by 2. If n is odd, the remainder is 1. If n is even (i.e., divisible by 2), the remainder is 0.
    5. Fix the typo in your last line.
     
  4. Apr 1, 2015 #3

    Mark44

    Staff: Mentor

    @acurate, did you figure this out?
     
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