Q : write products formed when polyester is heated with aqueous sodium

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    Aqueous Sodium
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Discussion Overview

The discussion revolves around the products formed when polyester is heated with aqueous sodium hydroxide, focusing on the hydrolysis process and the potential substitution of hydroxyl groups in the resulting carboxylic acid.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant asserts that hydrolysis occurs, producing alcohol and carboxylic acid, and questions whether the -OH in the carboxylic acid is replaced by -ONa.
  • Another participant clarifies that "heated" refers to the temperature increase, which may accelerate reactions, but does not inherently imply a reaction occurs.
  • A participant seeks clarification on whether the substitution of -OH with -ONa depends on the amount of sodium hydroxide present.
  • One participant agrees that knowing the amount of sodium hydroxide would be the best approach to determine the outcome.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the substitution of -OH with -ONa and agree that the amount of sodium hydroxide is a critical factor in determining the products formed. The discussion remains unresolved regarding the specific outcomes of the reaction.

Contextual Notes

The discussion does not clarify the exact conditions under which the hydrolysis occurs, nor does it resolve the implications of heating on the reaction dynamics.

charlotta
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Q : write products formed when polyester is heated with aqueous sodium hydroxide

I know is hydrolysis , and the product will be alcohol and carboxylic acid ... but will the -OH in carboxylic acid replaces with -ONa or not ??
It say heated with , but doesn't mean react .. so does heated means react ?
 
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Heated means heated. However, reactions are faster at elevated temperatures.

If there is enough base it will neutralize the acid.
 


thank you ..

so what you mean is that to determine whether is -OH or -ONa , we have to know the amount of sodium hydroxide ?
 


That would be the best approach.
 


ok.. thank you ...
 

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