1. Jan 31, 2008

### jesuslovesu

1. The problem statement, all variables and given/known data

y^2 - 2y = x^3 + 2x^2 + 2x + 3

2. Relevant equations

3. The attempt at a solution

Solve for y
How do you solve for y? my book says since that equation is quadratic in y, it can be solved as y = 1 +- sqrt(x^3 + 2x^2 + 2x + 4) but I have no idea how to do that...

all I can do is y(y-2) ...

2. Jan 31, 2008

### rock.freak667

Can you express $y^2-2y$ in the form $a(y+h)^2+k$?

3. Jan 31, 2008

### jesuslovesu

y^2 - 2y - K = 0
-k, -2y
K = x^3 + ....
Unfortunately, i seem unable to do so

4. Jan 31, 2008

### jesuslovesu

Oh wait, I forgot about completing the square, I got it thanks

5. Feb 1, 2008

### disregardthat

You can also use the quadratic formula, might be easier.