Quadratic equation word problem

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Barkley's canoe-rental business charges $12 per canoe and averages 36 rentals daily, but a price increase of $0.50 results in a loss of two rentals per day. To maximize income, the revenue function is established as R = pN, where N is the number of rentals defined by N = 36 - 4(p - 12). The income equation simplifies to I = 84p - 4p^2, indicating a quadratic relationship. The discussion focuses on deriving the optimal price to maximize income based on these equations. Understanding the link between price changes and rental decreases is crucial for solving the problem effectively.
musicgold
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1. Problem
Barkley runs a canoe-rental business on a small river in Pennsylvania. Currently, the
business charges $12 per canoe and they average 36 rentals a day. A study shows that
for every $.50 increase in rental price, the business can expect to lose two rentals per
day. Find the price that will maximize income.

2. The attempt at a solution
I found this problem on the internet. I can probably solve the problem manually, but I want to learn how to create a set of equation to describe this situation.
R= revenue, x= rental rate and t= number of rentals

R = x * t
R= 432 in a normal state.

I am not sure how to link a $0.50 change in x to a 2 unit change in t.

How should I go about this?

Thanks.
 
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If you increase the price by $0.50 then your revenue will now be

R=(x+0.5)(t-2)

Increase it again by another $0.50 and you now have?

What if you increase it n times?
 
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musicgold said:
1. Problem
Barkley runs a canoe-rental business on a small river in Pennsylvania. Currently, the
business charges $12 per canoe and they average 36 rentals a day. A study shows that
for every $.50 increase in rental price, the business can expect to lose two rentals per
day. Find the price that will maximize income.

2. The attempt at a solution
I found this problem on the internet. I can probably solve the problem manually, but I want to learn how to create a set of equation to describe this situation.
R= revenue, x= rental rate and t= number of rentals

R = x * t
R= 432 in a normal state.

I am not sure how to link a $0.50 change in x to a 2 unit change in t.

How should I go about this?

Thanks.

The demand (number of rentals per day) is given by
N = 36 - 4(p-12)
where ##p =## price ($) and ##N=## number rented per day. Note that when ##p = 12## we have ##N = 36##, as given in the problem. Note also that ##N## decreases by 4 when ##p## increases by 1 (that is, ##N## decreases by 2 when ##p## increases by 0.5).

The income is ##I = p N## because we have ##N## rentals and receive ##p##($) for each rental. Thus the daily income (in $) is
I = pN = p[36 - 4(p-12)] = 84 p - 4 p^2
 
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Thank you.
 

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