Quadratic Question Dealing With Perimeter

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Homework Help Overview

The problem involves determining the dimensions of a rectangular package with a square base that maximizes surface area, given that the sum of all edges measures 140 cm.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between perimeter and surface area, with attempts to derive expressions for both. Questions arise about how to express height in terms of width and how to maximize the surface area function.

Discussion Status

Participants are collaboratively exploring the problem, with some providing hints and suggestions for deriving the area expression. There is an ongoing dialogue about substituting variables and maximizing the area function.

Contextual Notes

There is a focus on using algebraic manipulation to relate dimensions and constraints, with some participants questioning the appropriateness of their approaches and assumptions regarding the relationships between variables.

kylepetten
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Homework Statement



Jillian is getting ready to send a holiday package in the mail. The rectangular package has a square base and the sum of all the edges of the package measures 140 cm. What dimensions will produce a package with the largest possible surface area?



Homework Equations



Let x = widths and y = heights



The Attempt at a Solution



P=8x + 4y
140 cm = 8x +4y
-4y = 8x - 140 cm
y = -2 + 35 cm

This is as far as I can get. Am I supposed to solve for x? Please lend me a hint. Thanks a bunch!
 
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hi kylepetten! :smile:
kylepetten said:
… What dimensions will produce a package with the largest possible surface area?

P=8x + 4y
140 cm = 8x +4y
-4y = 8x - 140 cm
y = -2 + 35 cm

This is as far as I can get.

ok so far … and now you need an expression for the area! :wink:
 
tiny-tim said:
hi kylepetten! :smile:


ok so far … and now you need an expression for the area! :wink:

SA = x^2 + x^2 + xy + xy + xy + xy
SA = 2x^2 + 4xy

That what you meant?
 
kylepetten said:
SA = x^2 + x^2 + xy + xy + xy + xy
SA = 2x^2 + 4xy

That what you meant?

(try using the X2 icon just above the Reply box :wink:)

Yup! :biggrin:

So if 2x + y is constant, how do you maximise x2 + 2xy ? :wink:
 
tiny-tim said:
(try using the X2 icon just above the Reply box :wink:)

Yup! :biggrin:

So if 2x + y is constant, how do you maximise x2 + 2xy ? :wink:


Am I off track by saying fill in -2x+35 for y?

Then use x = -b / 2a ?

Thanks for all the help, by the way.
 
Yep, that should do it! :smile:
 
tiny-tim said:
Yep, that should do it! :smile:

Thanks a lot! :approve:
 

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