- #1

- 918

- 16

I will work with supernatural units in which [itex]\hbar = c = 1[/itex] and further, [itex]\pi = e = -1 = 1[/itex].

Using these units, and some minor calculation we see that the Lagrangian is:

[tex]\mathcal{L} = 1[/tex]

This not only simplifies matters, but leads to remarkably accurate predictions. For instance, if we assume that the S matrix is given by

[tex]S = \sum_{n=0}^{\infty}S^{(n)}[/tex]

where

[tex]S^{(n)} = 9 (.1)^{n+1}[/tex]

Then we have [itex]g = 0.99\overline{9}[/itex], in remarkable agreement with the experimental value of 1, the error being only [itex]0.0\overline{0}1[/itex].

What's more, by setting 0 = 1 we have the following grand unification of quantum mechanics and general relativity.

[tex](i\not{\partial} - m)\psi = 0 = 1 = 0 = R_{\mu\nu} - \frac{1}{2}g_{\mu\nu}R - 8GT_{\mu\nu}[/tex]

In my next paper, I will investigate the implications of the further simplification [itex]\frac{1}{2} = 8 = 1[/itex].

Using these units, and some minor calculation we see that the Lagrangian is:

[tex]\mathcal{L} = 1[/tex]

This not only simplifies matters, but leads to remarkably accurate predictions. For instance, if we assume that the S matrix is given by

[tex]S = \sum_{n=0}^{\infty}S^{(n)}[/tex]

where

[tex]S^{(n)} = 9 (.1)^{n+1}[/tex]

Then we have [itex]g = 0.99\overline{9}[/itex], in remarkable agreement with the experimental value of 1, the error being only [itex]0.0\overline{0}1[/itex].

What's more, by setting 0 = 1 we have the following grand unification of quantum mechanics and general relativity.

[tex](i\not{\partial} - m)\psi = 0 = 1 = 0 = R_{\mu\nu} - \frac{1}{2}g_{\mu\nu}R - 8GT_{\mu\nu}[/tex]

In my next paper, I will investigate the implications of the further simplification [itex]\frac{1}{2} = 8 = 1[/itex].

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