Quantum Mechanics I, finding impuls wavefunction.

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SUMMARY

The discussion focuses on finding the normalized impulse wavefunction $$\phi(p)$$ from a Gaussian wavefunction $$\Psi(x, t=0)$$. The constant C is established as $$\sqrt{\sqrt{\frac{2 \alpha}{\pi}}}$$, and the impulse wavefunction is derived using the Fourier transform relation, resulting in a complex expression. Participants explore alternative methods for deriving impulse wavefunctions from position wavefunctions and discuss the expectation value of position, highlighting the challenge of computation. References to Merzbacher's "Quantum Mechanics" provide additional context for the problem-solving approach.

PREREQUISITES
  • Understanding of Gaussian wavefunctions in quantum mechanics
  • Familiarity with Fourier transform techniques
  • Knowledge of expectation values in quantum mechanics
  • Basic principles of quantum mechanics as outlined in Merzbacher's "Quantum Mechanics" (2nd ed)
NEXT STEPS
  • Research the properties of Gaussian wavefunctions in momentum space
  • Study the Fourier transform of wavefunctions in quantum mechanics
  • Learn about expectation values and their calculations in quantum systems
  • Examine advanced topics in quantum mechanics from Merzbacher's "Quantum Mechanics" (2nd ed)
USEFUL FOR

Students and researchers in quantum mechanics, particularly those working with wavefunctions and Fourier transforms, as well as educators seeking to deepen their understanding of impulse wavefunctions and expectation values.

milkism
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Homework Statement
Find the impuls wavefunction phi(p) from the position wavefunction.
Relevant Equations
Look solution.
I have this following Gaussian wavefunction.
1705233351985.png

I found the constant C to be $$\sqrt{\sqrt{\frac{2 \alpha}{\pi}}}$$.
Now they're asking me to find the normalized impuls wavefunction $$\phi(p)$$. I tried to use the fourier transform relation
$$\phi (p) = \int e^{-\frac{i ( p x)}{\hbar}} \Psi (x,t=0) dx$$
and i got a long answer
$$\sqrt{\sqrt{\frac{2 \alpha}{\pi}}} \sqrt{\frac{\pi}{\alpha}} e^{-\frac{q^2}{4\alpha} + \frac{pq}{2 \alpha \hbar} - \frac{p^2}{4 \alpha \hbar ^2}}$$
Is there an other way to solve this? Because next question is to find the expectation value of position from the normalized impuls wavefunction, which is going to be very hard.
 
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Is there a better way to find impuls wavefunctions from position wavefunctions?
 
Any other way will of course give the same result.
 
milkism said:
I found the constant C to be
How ? [edit] never mind o:)
milkism said:
Because next question
Can you please post the complete problem statement ?

##\ ##
 
BvU said:
How ?
Can you please post the complete problem statement ?

##\ ##
$$\int_{-\infty}^{\infty} \Psi ^{*} \Psi dx =1, \int_{-\infty}^{\infty} C^2 e^{-2 \alpha x^2} dx = C^2 \sqrt{\frac{\pi}{2\alpha}} = 1$$
 
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Calculate the corresponding normalized wave function φ(p) in momentum space. Explicitly compute, based on the knowledge of φ(p), the expectation value 〈x〉.
 
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milkism said:
and i got a long answer
##e^{-{1\over 4\alpha}\left(q-p\right )^2}\ ## doesn't look all that bad to me ...
a peak around p = q, so the exercise will probably end up at something moving to the right with momentum ##q##

(did you check there is no ##i## in there ?)

The exercise reminded me of the treatment in Merzbacher, QM 2nd ed (1970 !) chapter 2.2

Next step was $$\psi(x,t) = {1\over \sqrt{2\pi}}\int_{-\infty}^{+\infty} \phi(k) e^{i(kx-\omega t}) dk$$ but I'm too rusty to comfortably work that out ( i.e. ##\omega(k)## )

##\ ##
 
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