Quantum Mechanics I, finding impuls wavefunction.

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Homework Help Overview

The discussion revolves around finding the normalized momentum wavefunction, φ(p), from a given Gaussian position wavefunction, Ψ(x, t=0). Participants are exploring the Fourier transform relationship and its implications in quantum mechanics.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of the Fourier transform to derive φ(p) and express concerns about the complexity of the resulting expression. Questions arise about alternative methods for obtaining the momentum wavefunction and the implications for calculating the expectation value of position.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning the methods used. Some express uncertainty about the results and seek clarification on the problem statement. There is no explicit consensus, but various approaches are being considered.

Contextual Notes

Participants note the need for the complete problem statement to ensure all aspects are addressed. There are references to specific calculations and the normalization condition for the wavefunction, indicating constraints in the problem setup.

milkism
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Homework Statement
Find the impuls wavefunction phi(p) from the position wavefunction.
Relevant Equations
Look solution.
I have this following Gaussian wavefunction.
1705233351985.png

I found the constant C to be $$\sqrt{\sqrt{\frac{2 \alpha}{\pi}}}$$.
Now they're asking me to find the normalized impuls wavefunction $$\phi(p)$$. I tried to use the fourier transform relation
$$\phi (p) = \int e^{-\frac{i ( p x)}{\hbar}} \Psi (x,t=0) dx$$
and i got a long answer
$$\sqrt{\sqrt{\frac{2 \alpha}{\pi}}} \sqrt{\frac{\pi}{\alpha}} e^{-\frac{q^2}{4\alpha} + \frac{pq}{2 \alpha \hbar} - \frac{p^2}{4 \alpha \hbar ^2}}$$
Is there an other way to solve this? Because next question is to find the expectation value of position from the normalized impuls wavefunction, which is going to be very hard.
 
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Is there a better way to find impuls wavefunctions from position wavefunctions?
 
Any other way will of course give the same result.
 
milkism said:
I found the constant C to be
How ? [edit] never mind o:)
milkism said:
Because next question
Can you please post the complete problem statement ?

##\ ##
 
BvU said:
How ?
Can you please post the complete problem statement ?

##\ ##
$$\int_{-\infty}^{\infty} \Psi ^{*} \Psi dx =1, \int_{-\infty}^{\infty} C^2 e^{-2 \alpha x^2} dx = C^2 \sqrt{\frac{\pi}{2\alpha}} = 1$$
 
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Calculate the corresponding normalized wave function φ(p) in momentum space. Explicitly compute, based on the knowledge of φ(p), the expectation value 〈x〉.
 
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milkism said:
and i got a long answer
##e^{-{1\over 4\alpha}\left(q-p\right )^2}\ ## doesn't look all that bad to me ...
a peak around p = q, so the exercise will probably end up at something moving to the right with momentum ##q##

(did you check there is no ##i## in there ?)

The exercise reminded me of the treatment in Merzbacher, QM 2nd ed (1970 !) chapter 2.2

Next step was $$\psi(x,t) = {1\over \sqrt{2\pi}}\int_{-\infty}^{+\infty} \phi(k) e^{i(kx-\omega t}) dk$$ but I'm too rusty to comfortably work that out ( i.e. ##\omega(k)## )

##\ ##
 
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