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DrChinese said:Any entangled system does not factorize, according to QM.
Bell's factorization criterion is not exactly the same as the criterion that the wave function (or density matrix) factors, because is talking about whether the probabilities for outcomes of measurements factors, rather than whether the wave function factors. Those aren't exactly the same criteria.
I gave an example earlier in this thread, but I'll repeat it: Let |\psi, u\rangle be the one-electron state in which the electron is definitely spin-up along the z-axis, and has probability amplitude \psi(\vec{r}) of being found in position \vec{r}. Let |\phi, d\rangle be the one-electron state in which the electron is definitely spin-down along the z-axis, and has probability amplitude \phi(\vec{r}) of being found in position \vec{r}. Then we can form the two-electron state:
|\Psi\rangle = |\psi, u\rangle \otimes |\phi, d\rangle - |\phi, d\rangle \otimes |\psi, u\rangle
That is an entangled state. But if the two spatial dependencies \phi(\vec{r}) and \psi(\vec{r}) have non-overlapping support (there is no place where both are nonzero), then the corresponding probabilities for spin measurements at two distant locations \vec{r_1} and \vec{r_2}, where \psi(\vec{r_1}) and \phi(\vec{r_2}) are both nonzero, factor:
P(A \& B | \vec{\alpha}, \vec{\beta}) = |\psi(\vec{r_1})|^2 cos^2(\theta_1/2) |\phi(\vec{r_1})|^2 sin^2(\theta_2/2)
(where A is true if an electron is found to have spin-up along \vec{\alpha} at location \vec{r_1}, and B is true if an electron is found to have spin-up along \vec{\beta} at location \vec{r_1}, and \theta_1 is the angle between \vec{\alpha} and the z-axis, and \theta_2 is the angle between \vec{\beta} and the z-axis.)