- #1

- 30

- 0

## Homework Statement

An object of mass m is dropped from a tower of height d. Show that according to

quantum mechanics the closest the object can fall on average to the base of the

tower is:

(d/g)^(1/4) (h/m)^(1/2)

## Homework Equations

I don't know - that is the problem to know what to use.

## The Attempt at a Solution

Using v^2=u^2+ 2as => velocity when mass reaches ground is v=√2gd

so momentum p=mv=m√2gd

using Uncertainty Principle ∆x∆p=h => ∆x=h/∆p=h/(m√2gd)

This is not the right answer so what have I done wrong?