Quantum Operators - Eigenvalues & states

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SUMMARY

The discussion centers on the eigenvalues and eigenstates of the operator \(\hat{H}_0 = \frac{\hbar \omega}{2}\left[\left|1\right\rangle\left\langle1\right| - \left|0\right\rangle\left\langle0\right|\right]\). The eigenvalues calculated are -1 and 1, represented in matrix form as \(\frac{\hbar \omega}{2}\left( \begin{array}{cc} -1 & 0 \\ 0 & 1 \\ \end{array} \right)\). The confusion arises when substituting these eigenvalues back into the eigenvalue equation \(H\mathbf{x} = \lambda\mathbf{x}\), leading to seemingly contradictory results. The resolution involves recognizing that eigenvectors can be scaled, allowing for flexibility in choosing components of the solution.

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  • Understanding of quantum mechanics concepts, specifically operators and eigenvalues.
  • Familiarity with linear algebra, particularly matrix representation of operators.
  • Knowledge of eigenvalue equations and their solutions.
  • Proficiency in manipulating complex numbers and vectors in quantum contexts.
NEXT STEPS
  • Study the derivation and implications of eigenvalues in quantum mechanics.
  • Learn about the significance of eigenstates and their role in quantum systems.
  • Explore the concept of operator matrices in quantum mechanics, focusing on Hermitian operators.
  • Investigate the normalization of eigenvectors and the implications of scaling solutions.
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Students and professionals in quantum mechanics, physicists working with quantum operators, and anyone interested in the mathematical foundations of quantum theory.

knowlewj01
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Homework Statement



an operator for a system is given by

\hat{H}_0 = \frac{\hbar \omega}{2}\left[\left|1\right\rangle\left\langle1\right| - \left|0\right\rangle\left\langle0\right|\right]

find the eigenvalues and eigenstates

Homework Equations





The Attempt at a Solution



so i formulated this operator as a matrix

\frac{\hbar \omega}{2}<br /> \left( \begin{array}{cc}<br /> -1 &amp; 0 \\<br /> 0 &amp; 1 \\ \end{array} \right)<br />
and found the eigenvalues to be -1 and 1

but when i put them back into the eigenvalue equation Hx = λx [x is a 2 row column vector with elements x1 and x2]
i get nonsense, something like

for λ=1:
x1 = -x1
x2 = x2

for λ=-1:
x1 = x1
x2 = -x2

am i missing something important here?

thanks.
 
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knowlewj01 said:
but when i put them back into the eigenvalue equation Hx = λx [x is a 2 row column vector with elements x1 and x2]
i get nonsense, something like

for λ=1:
x1 = -x1
x2 = x2

for λ=-1:
x1 = x1
x2 = -x2

am i missing something important here?

thanks.

Those look fine with no nonsense. Try solving each set of equations. One equation will fix one component, while the other doesn't fix anything. This is because, as with any eigenvector equation, a multiple of a solution is still a solution. You should just pick a convenient choice for the unknown variable in order to write down a solution.
 

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