Quantum Oscillator: Pendulum Energy Differences & Observability

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Homework Help Overview

The discussion revolves around the energy differences between quantum states of a pendulum modeled as a quantum oscillator, specifically for a pendulum of length 1 meter. Participants are also considering the observability of these energy differences.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the formula for energy states, with one suggesting that the energy differences might be simply 1. Others question the observability of these low energy differences and discuss the need for additional parameters, such as mass, to fully address the problem.

Discussion Status

The discussion is active with various interpretations being explored. Some participants have provided insights into calculating energy differences and the implications of missing information, such as the mass of the pendulum. There is no explicit consensus on the approach or the observability of the energy differences.

Contextual Notes

Participants note that the original problem lacks information about the mass of the pendulum, which is crucial for calculations. There is also a mention of the assumption that the pendulum behaves in harmonic oscillation.

GreenLRan
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Homework Statement



Assuming a pendulum to behave like a quantum oscillator, what are the energy differences between the quantum states of a pendulum of length 1m? Are such differences observable?

Homework Equations





The Attempt at a Solution



would the energy differences just be 1 since for each energy state n you have E_n=(n+1/2)h_bar*sqrt(k/m)? This would not be observable either since these are such low energies... correct?
 
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Compare E_n to E_n+1
 
I think they want you to calculate the energy in joules.
 
But wouldn't they have provide him with the mass of the pendulum?
in his statement they only gave him the length , I think it's like robb said , a comparison between E_n and E_n+1
 
No they don't, it's a pendulum in harmonic oscillation, so you can say its angular frequency is simply sqrt(g/L), then solve for (1/2)hw
 

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