Quantum Spin: Forgetting, Entanglement & Change

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 5K views
Xori
Messages
46
Reaction score
0
My understanding is that when you measure an electron's spin on on Axis A, and then on Axis B, the spin on Axis A is "forgotten" and can be something different next time you measure it. Is this correct?

If it is, then how does this work across entanglement? If you measure electron A's spin at Axis A, then you know electron B's spin is the opposite. But if you then measure electron's A spin again on Axis B, you can potentially "change" electron B's spin on Axis A?
 
Physics news on Phys.org
Who says that would "change" the other electron?

If A and B were entangled, measuring A once will give you information about both A and B. It will also generally break the entanglement, so further measurements of A tell you nothing further about B.

For example, if you made a third measurement of A (on axis A for the second time, giving a random result) and then measured B, you would find it correlated with the first (rather than third) measurement of A.
 
Damn, now I got to think of another way to communicate FTL.
 
Good luck with that.
 
Xori said:
My understanding is that when you measure an electron's spin on on Axis A, and then on Axis B, the spin on Axis A is "forgotten" and can be something different next time you measure it. Is this correct?
Have a clear answer for the first part: after the mesurement of spin along the B axis the particle will be in an eigenstate of spin pojected on B. Unless A and B are collinear, this is not an eigenstate of spin projected on A, thus if we make a third measuremnet (aling A again), the probability distribution will no longer be a Kronicker-delta