Quantum State Evolution of a Free Particle at a Defined Position

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SUMMARY

The quantum state of a free particle at a defined position r0 at time t=0 is represented as an eigenstate of position with eigenvalue r0. To analyze the evolution of this state over time, one must utilize the evolution operator in conjunction with the Hamiltonian of a free particle. The wave function for this scenario is characterized by a delta function, which can be transformed into momentum space using Fourier transforms, allowing for straightforward time evolution in the momentum basis. After evolving in momentum space, one can revert to position space by applying the inverse Fourier transform.

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bluesunday
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The question is: what is the quantum state of a free particle t time after its detection at the position r0 in t=0?

I know I have to use the evolution operator with the hamiltonian of a free particle. My actual problem is more stupid than that: I don't really know how to express the STATE of a free particle of well defined position (r0 in t=0, in this case)
 
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If we know exactly the position of the particle at t=0, does this mean that at this time its state is an eigenstate of position, with eigenvalue r0? How can I put that into:

[URL]http://upload.wikimedia.org/math/1/0/3/10317da44bf13fbd709cd642c5143b9f.png[/URL]

Should I just skip Dirac notation and work with wavefuncions? I don't know... Please help.
 
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I'd work in the momentum basis for this problem.

The wave function for a free particle at a definite position is a delta function.

Fourier transform this wavefunction into momentum space and then time evolve. It should be straightforward in the momentum basis.

If you need your answer in position space, then you can always Fourier transform back.
 
Last edited:

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