sunrah
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(please note this is similar to a homework question I have posted but it is not the same and here I am just trying to understand a concept)
In a book I was reading it said
[itex] \Delta^{+} \longrightarrow n + \pi^{+}[/itex]
is a viable process via the strong force because all that is needed is a down antidown quark pair, which can be provided via the strong force. My question is why? If [itex]\Delta^{+}[/itex] is uud and [itex]\Delta^{+}\pi^{+}[/itex] is udd + [itex]u\bar{d}[/itex] we can see that the right hand side only has one antidown quark therefore there has only been one quark-antiquark pair created. Converting one quark into two only creates one extra particle effectively so I see a deficit on the left hand side.
Please can someone explain
In a book I was reading it said
[itex] \Delta^{+} \longrightarrow n + \pi^{+}[/itex]
is a viable process via the strong force because all that is needed is a down antidown quark pair, which can be provided via the strong force. My question is why? If [itex]\Delta^{+}[/itex] is uud and [itex]\Delta^{+}\pi^{+}[/itex] is udd + [itex]u\bar{d}[/itex] we can see that the right hand side only has one antidown quark therefore there has only been one quark-antiquark pair created. Converting one quark into two only creates one extra particle effectively so I see a deficit on the left hand side.
Please can someone explain
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What you have written does not conserve charge.
