Question about changing magnetic flux

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SUMMARY

The discussion focuses on calculating the change in magnetic flux for a 200-loop coil with a cross-sectional area of 8.5 cm² subjected to a decreasing external magnetic field from 0.060 T to 0.020 T over 12 milliseconds. The correct formula for magnetic flux is Φ = N * B * A * cos(φ), where N is the number of loops, B is the magnetic field, A is the area, and φ is the angle between the magnetic field and the normal to the coil's surface. Since the magnetic field and area are aligned, cos(φ) equals 1, simplifying the calculation to ΔΦ = N * (B_initial - B_final) * A.

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Homework Statement



A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed out of the plane of the page. The external field decreases to 0.020 T in 12 milliseconds.
What is the magnitude of the change in the external magnetic flux enclosed by the coil?

Homework Equations



\Phim = A * B

The Attempt at a Solution


Ive tried solving for both values of magnetic flux at each time and finding their difference. However, I still seem to get it wrong. I don't know If I am missing something, any help or tips would be greatly appreciated.
 
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i believe it would just be the initial flux - the final flux...

the full equation you want is \Phi= N*B*A*cos(\phi)
(N = the number of turns of the coil)

however the direction of the area and the magnetic field are the same so cos(phi) = 1
just convert 8.5 cm2 to m2 which is 8.5 * 10-4

so... N(.06T)(A) - N(.02T)(A), just plug in your numbers...i believe this is right anyway, someone should check my work
 

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