Question about frictional and normal force

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SUMMARY

The discussion centers on calculating the frictional force acting on a stationary wall with a mass of 150 kg and a coefficient of friction of 2. The frictional force formula, Fr = (mu)(Fn), is referenced, but the normal force (Fn) must be determined to use this equation effectively. It is clarified that if there is no movement between the wall and the person pushing it, the frictional force will be zero, as static friction only acts to prevent motion. The correct interpretation of the frictional force equation is |Fr| <= mu |Fn|.

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  • Understanding of static friction and its properties
  • Familiarity with Newton's laws of motion
  • Knowledge of the coefficient of friction and its implications
  • Basic algebra for manipulating equations
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imagesparkle
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Homework Statement


Okay so there is a wall that has a mass of 150 kg and I am pushing it but the wall does not move. The coefficient of friction is 2 and I am trying to find the frictional force using the frictional force formula. Although, I need the normal force in which I am using to push the wall but don't know how to find the normal force.

Homework Equations


Fr = (mu)(Fn)

The Attempt at a Solution

 
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imagesparkle said:

Homework Statement


Okay so there is a wall that has a mass of 150 kg and I am pushing it but the wall does not move. The coefficient of friction is 2 and I am trying to find the frictional force using the frictional force formula. Although, I need the normal force in which I am using to push the wall but don't know how to find the normal force.

Homework Equations


Fr = (mu)(Fn)

The Attempt at a Solution

You need to describe the set up better. Frictional force between what two objects - you and the wall?
Friction acts parallel to the surfaces in contact. If there is no movement and no other forces in that direction then the frictional force will be zero, regardless of the coefficient. The static frictional force is only as large as it needs to be to prevent relative motion. The correct equation is |Fr| <= mu |Fn|.
 

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