What is the recommended method to reduce gamma ray exposure?

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SUMMARY

The discussion centers on the methods to reduce gamma ray exposure, particularly in relation to photographic plates. It is established that increasing gas pressure in a container does not affect the blackened region on the photographic plate, as gamma rays do not lose energy through ionizing air molecules like charged particles do. Instead, gamma photons either pass through or are absorbed by atoms, with denser air leading to a reduction in photon flux. Effective shielding materials for gamma rays are also a key consideration in reducing exposure.

PREREQUISITES
  • Understanding of gamma ray properties and behavior
  • Knowledge of ionization processes in gases
  • Familiarity with photographic plate exposure principles
  • Awareness of radiation shielding materials
NEXT STEPS
  • Research effective gamma ray shielding materials such as lead and concrete
  • Learn about the principles of ionization and its effects on radiation
  • Study the interaction of gamma rays with matter, focusing on photon absorption
  • Explore methods to measure gamma ray flux and exposure levels
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Radiation safety professionals, physicists, and anyone involved in radiation protection or gamma ray research will benefit from this discussion.

Clara Chung
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A gamma ray source emits gamma ray to a photographic plate in a container. The book said the blacked region on the photographic plate wouldn't be affected if the gas pressure of the container was increased.
However, I think that the gamma ray will ionise more air molecules and lose more energy though ionising air molecules. Therefore, the photographic film will be hit by less photons of gamma ray and blackened less.
Am I right or wrong?
 
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Clara Chung said:
A gamma ray source emits gamma ray to a photographic plate in a container. The book said the blacked region on the photographic plate wouldn't be affected if the gas pressure of the container was increased.
Which book?
What is the significance of the blacked part of the photographic plate?
I cannot tell what the book is talking about without a more detailed description.

However, I think that the gamma ray will ... lose more energy though ionising air molecules. Therefore, the photographic film will be hit by less photons of gamma ray and blackened less.
Am I right or wrong?
...the bolded part is incorrect. Gamma rays do not lose energy from ionizing air molecules the way a massive charged particle does. Instead, gamma photons are either allowed to pass or absorbed completely by an atom it gets close to. The ray does lose more photons in denser air though... so what you want to consider is how dense the air would have to get for the weakened flux to show up on the plate?

What does it usually take to reduce gamma ray flux? What do people normally use for shielding?
 
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