Question about inverse of matrix

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    Inverse Matrix
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SUMMARY

The discussion centers on proving that the inverse of the matrix ##\begin{bmatrix}As+B \\ C \end{bmatrix}## has no terms with ##s## or higher degree, given that ##\begin{bmatrix}A \\ C \end{bmatrix}## is invertible and ##A## has full row rank. The participant manipulates the matrix using properties of determinants and matrix rank, ultimately seeking to relate the determinant of ##\begin{bmatrix}As \\ C \end{bmatrix}## to the powers of ##s##. The insights gained from the discussion clarify how to leverage the rank property of ##A## to derive entries of the full inverse matrix.

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Homework Statement


[/B]
Given this matrix
##\begin{bmatrix}As+B \\ C \end{bmatrix}##
which is invertible and ##A## has full row rank. I would like to show that its inverse has no terms with ##s## or higher degree if
##\begin{bmatrix}A \\ C \end{bmatrix}##
is invertible.

Homework Equations



The Attempt at a Solution



The only thing I have concluded is that you can manipulate it like this:

##\begin{bmatrix}I & 0 \\ 0 & sI \end{bmatrix} \begin{bmatrix}As+B \\ C \end{bmatrix}=\begin{bmatrix}As+B \\ Cs \end{bmatrix}=s\begin{bmatrix}A \\ C \end{bmatrix}+\begin{bmatrix}B \\ 0 \end{bmatrix}##
where each ##I## is conformable with the matrix product. Not sure how to take this any further, though. I think my main problem is that I don't know how to use the rank property of ##A##.
 
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What can you say about the determinant of ##\begin{bmatrix}As \\ C \end{bmatrix}## in terms of powers of s?
How can you use the determinant (of the original matrix) to find entries of the full inverse matrix?
 
Thank you for your hints, pushed me into the right direction and helped me prove the statement!
 
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