## Homework Statement

If I just had the set containing $\pi$ on the real line.
So this is an isolated point. Is this set closed?

## The Attempt at a Solution

I think this set is closed because it contains its limit points, because it only has one point.

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Hmm, that's an interesting question. I guess it would be closed because that's the only point in the set, and there's no option for an e-neighbourhood around it.

Dick