Question about Proof of Inverse Function

Click For Summary
The discussion centers on understanding the proof of the Inverse Function Theorem as presented in baby Rudin. Associating the function φ(x) with each point y helps establish that f(x) is one-to-one by demonstrating that φ is a contraction mapping. By showing that |φ'(x)| is less than ½, the contraction principle can be applied, confirming that φ must be one-to-one for every y. Additionally, the question about the value of A⁻¹ when f'(a) = A and f(x) = x² highlights the complexities involved in differentiating and inverting functions. Overall, the conversation emphasizes the importance of fixed points and contraction mappings in proving the theorem.
transphenomen
Messages
52
Reaction score
0
I am reading the proof of the Inverse Function Theorem in baby Rudin and I have a question about it. How does associating a function phi(x) (equation 48) with each point y tell us anything about if f(x) is one-to-one? I'll show the proof below. Also, if f'(a) = A, and f(x)=x2, what would A-1 be?
 

Attachments

  • Inverse 1.jpg
    Inverse 1.jpg
    43.1 KB · Views: 680
  • Inverse 2.jpg
    Inverse 2.jpg
    37.3 KB · Views: 602
  • Inverse 3.jpg
    Inverse 3.jpg
    59.3 KB · Views: 572
Physics news on Phys.org
The exact same equation had me freaking out for a while.

You can think of φ(x) = x + A⁻¹(y - f(x)) as coming from f(x) = f(x₀) + f'(x)(x - x₀),
& it's a way of introducing the concept of a fixed point so we can use the contraction
principle. You basically want to show that |φ'(x)| < ½ & then use theorem 9.19
|φ(b) - φ(a)| ≤ M(b - a) & with M = ½ you have a contraction mapping, thus by the
contraction principle you have that for every y it's associated function φ must be 1-1.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K