Question about rectangles in R^n

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SUMMARY

The discussion centers on the definition of rectangles in R^n, specifically regarding the Cartesian product of intervals. It confirms that the Cartesian product [a1] * [a2, b2] * ... * [an, bn] can be considered a rectangle in R^n, despite being a degenerate case when one or more intervals are singletons. The set [a1, a1] results in a singleton set, leading to the conclusion that such degenerate rectangles are valid within the broader context of n-dimensional geometry. This extension of definitions allows for a more comprehensive understanding of rectangles in mathematical discourse.

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JG89
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I know that by definition the cartesian product of [a1, b1], [a2,b2], ..., [an. bn] is a rectangle in R^n. Are we "allowed" to call the cartesian product [a1] * [a2, a2] * ... * [an, an] a rectangle in R^n? I know that by definition [a,b] = {x: a <= x <= b}. The set [a1,a1] = {x: a1 <= x <= a1} which is just the singleton set {a1}. Thus the rectangle [a1] * [a2, a2] * ... * [an, an] is just the cartesian product a1*a2*a3*..*an, where each ai is a real number, which hardly looks like a rectangle if we draw it in say, R^2 or R^3.
 
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You could call it a degenerate rectangle. It is convenient to extend definitions to degenerate cases, because they occur naturally. In that way you do not need to explicitly mention them whenever you talk about an n-dimensional rectangle.
 

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