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Question about resonating in a closed tube.

  1. Jul 23, 2012 #1
    1. The problem statement, all variables and given/known data
    A closed tube resonates at 440 Hz when it is 0.195 m long and 0.586 m long. Determine the speed of sound. How do I do this?

    2. Relevant equations


    3. The attempt at a solution
    v= 440 (4L) I'm just not sure how to use both lengths given, can someone help me out?
  2. jcsd
  3. Jul 23, 2012 #2
    You do not know that wavelength = 4L.
    The wavelength can be 2(L/1), 2(L/2), 2(L/3), 2(L/4), 2(L/5)....etc
    You also know that v = f x wavelength. And v does not change
    The values you have been given should enable you to write down 2 simultaneous equations from which you can get the answer.
    Last edited: Jul 23, 2012
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