Question about resonating in a closed tube.

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Homework Statement


A closed tube resonates at 440 Hz when it is 0.195 m long and 0.586 m long. Determine the speed of sound. How do I do this?

Homework Equations



wavelength=4L
v=fw

The Attempt at a Solution


v= 440 (4L) I'm just not sure how to use both lengths given, can someone help me out?
 
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You do not know that wavelength = 4L.
The wavelength can be 2(L/1), 2(L/2), 2(L/3), 2(L/4), 2(L/5)...etc
You also know that v = f x wavelength. And v does not change
The values you have been given should enable you to write down 2 simultaneous equations from which you can get the answer.
 
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