Question about simplifying Sigma notation

  • #1
410
11
Hello everyone!

I have this expression which I have to simplify:
i=1log(n) 1(log(n) - i)

And my book apparently simplifies it to being log(n).
I am struggling to figure out why this is the case. Could anyone help?

Thanks!
 

Answers and Replies

  • #2
15,142
12,873
What is ##e_i=1^{\text{ insert any integer }}## and what is ##\sum_{i=1}^{n} a_i## if you write it out with dots? And finally set ##a_i=e_i##.
 
  • #3
andrewkirk
Science Advisor
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Firstly, how many terms are there in the sum - ie how many things are being added together?

Secondly, what is the value of each term? What do you get when you raise 1 to the power of any other real number?

EDIT: Uh oh - Jinxed again!
 
  • #4
410
11
Ohh, I see thanks!

We add 1 log(n) times over and over again!

Thanks for the help everyone!
 

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