Does the placement of weight affect tension in 3D?

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SUMMARY

The placement of weight in a rectangular box significantly affects the tension in the strings connected to it. When a weight is placed at the center of the box, the tension is distributed evenly across the strings. However, if the weight is positioned at a corner, the center of mass shifts, creating torque that increases tension in one or two strings to counterbalance the gravitational force. This results in a differential tension based on the weight's location, confirming that the weight vector influences string tension.

PREREQUISITES
  • Understanding of basic physics concepts such as force, torque, and center of mass.
  • Familiarity with vector analysis, particularly in three-dimensional space.
  • Knowledge of tension in strings and its relation to weight distribution.
  • Experience with static equilibrium principles in mechanics.
NEXT STEPS
  • Explore the principles of torque and its calculation in three-dimensional systems.
  • Study the effects of weight distribution on static equilibrium in mechanics.
  • Learn about vector decomposition in physics to analyze forces in different directions.
  • Investigate real-world applications of tension in structures and materials under load.
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Physics students, mechanical engineers, and anyone interested in understanding the dynamics of tension and weight distribution in three-dimensional systems.

Icah
If you have a rectangular box connected on 3 sides with strings, and you hold all the strings together at a point, with your hand; then you put a weight in the center of the box, which is open, would the tension on the strings differ than if you put the weight at a corner. Please describe it to me in detail. I assume it would not because the weight vector is always in the negative z direction, but looking at it tells me otherwise...
 
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If the center of mass is not in the center of the box, due to a mass placed offcenter, then there will be a torque about the center (created by gravity), so additional tension on one or two strings (upward) will create an offsetting torque.
 
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scottdave said:
If the center of mass is not in the center of the box, due to a mass placed offcenter, then there will be a torque about the center (created by gravity), so additional tension on one or two strings (upward) will create an offsetting torque.
Thank you
 
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