Question about the Derivation of the Stream-function for a Doublet

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Discussion Overview

The discussion revolves around the derivation of the stream function for a doublet in fluid dynamics. Participants are exploring the mathematical formulation and implications of the stream function, particularly in relation to the placement of sources and sinks and the resulting fluid velocities.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the necessity of dividing by the distance between two sources before taking the limit, seeking clarity on the reasoning behind including a \(\frac{1}{s}\) term.
  • Another participant notes that swapping the locations of the source and sink results in fluid velocities that are in opposite directions, suggesting that this is consistent with physical expectations.
  • A participant expresses uncertainty about the implications of the division by \(\frac{1}{s}\) in the context of the limit as the two charges approach each other.

Areas of Agreement / Disagreement

Participants generally agree on the physical implications of the fluid velocities when the source and sink are swapped, but there remains uncertainty and disagreement regarding the mathematical reasoning behind the division by \(\frac{1}{s}\).

Contextual Notes

The discussion highlights the need for clarity on specific mathematical steps and assumptions, particularly regarding the limit process and the role of the \(\frac{1}{s}\) term in the derivation.

Master1022
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TL;DR
This is a question about the derivation of the stream-function of a doublet using potential flow theory
Hi,

I just wanted to ask a question about the derivation of the stream function \psi for a doublet. In the pictures below is a derivation (in this one the source is on the left and the sink is on the right). I understand everything in the left photo, however my questions are:

1) Why do we divide by the distance between two sources s before taking the limit? I cannot really understand the reason provided. I understand that the sources will cancel out, but am unclear as to why that means that we need to counter that by including a \frac{1}{s} term.

2) Why does the derivation come out differently if we swap the placements of the source and sink? Intuitively, I feel that I have made an algebraic error, but I fail to see it. If we place the source on the right and the sink on the left, then we will get:
\psi = \frac{m}{2 \pi} \theta_{source} - \frac{m}{2 \pi} \theta_{sink} = \frac{m}{2 \pi} \left( atan(\frac{y}{x-s}) - atan(\frac{y}{x+s}) \right). Now we will get the same expression as before (except we have +m instead of -m), except we will end up with a different sign at the end. Surely, the end result should be the same irrespective of the original geometry.

I would appreciate any help. Thanks in advance.

Screen Shot 2020-01-12 at 12.03.18 PM.png
Screen Shot 2020-01-12 at 12.03.24 PM.png
 
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If you swap the locations, the fluid velocities (calculated from the derivatives of the stream function) are, as expected physically, in the opposite direction. So what's the problem?
 
Chestermiller said:
If you swap the locations, the fluid velocities (calculated from the derivatives of the stream function) are, as expected physically, in the opposite direction. So what's the problem?
Ah yes, that is true. Thank you.

Do you know the reason behind the division by \frac{1}{s}?
 
Master1022 said:
Ah yes, that is true. Thank you.

Do you know the reason behind the division by \frac{1}{s}?
You are determining the limit as the two charges are very close together.
 
Chestermiller said:
You are determining the limit as the two charges are very close together.
I understand the intuition, but why does that mean that we need a \frac{1}{s} term
 

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