Question about unique real number

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Homework Help Overview

The discussion revolves around a proof in calculus regarding the property of real numbers, specifically the statement "If a + b = a + c, then b = c." The original poster is exploring the implications of this statement, particularly in relation to the uniqueness of the number zero.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definition of the zero number and its uniqueness. The original poster questions the reasoning behind the assertion that zero is unique, while others suggest using the proven property to establish this uniqueness.

Discussion Status

The conversation has progressed with participants providing insights and clarifications. The original poster indicates that their confusion has been resolved, suggesting that helpful guidance has been shared throughout the discussion.

Contextual Notes

There is an emphasis on the axiomatic definitions of real numbers and the properties of the identity element. The original poster notes a potential ambiguity in the axioms regarding the existence of a unique zero.

citea
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hello guys I am new in this forum
i start to self learn calculus tom apostol (in my college we got another book)
i start from the very beginning of the chapter. so this not really a homework. if i post thread in wrong sub-forum please remind me :)

Homework Statement



prove : If a+b = a+c, then b = c.

Homework Equations



this also prove zero number is unique.

The Attempt at a Solution



the prove was easy

using AXIOM EXISTENCE OF IDENTITY ELEMENTS & ASSOCIATIVE

there is a number y such that y + a = O
then
y+(a+b) = y+(a+c)

(y+a)+b=(y+a)+c

0+b=0+c

b=c

but why in the book say this also prove number 0 is unique? in other words only one real number have the property zero?!

thank u :)
 
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How did you define the zero number?
 
R136a1 said:
How did you define the zero number?

axiom says : there exist real number denote by 0, such that for every real x, we have x+0=x

see the underlined, it doesn't say : there exist ONE real number.
so we have to prove only exactly one real number denote by 0. but i still don't get it how to prove this.. :)
 
Can you see how to use the result you have just proved:

a + b = a + c => b = c

To prove that there is only one 0?
 
Assume there are two real numbers 0 and 0'. Both satisfy x+0 = x and x+0' = 0' for all x. Can you deduce 0 = 0'?
 
ok guys thanks for the help..
i don't have problem anymore.. its clear now
 

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