Question based on Lenses -O level/gcse

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SUMMARY

The discussion focuses on the application of the thin lens equation and the concept of magnification in optics. Participants clarify the definition of magnification as the ratio of image height to object height, emphasizing the importance of accurately determining the lengths of the image and object. The specific values discussed include an object length of 20 cm and an image length of 50 cm. Additionally, the method of drawing light rays to locate the image is highlighted as a crucial step in solving lens problems.

PREREQUISITES
  • Understanding of the thin lens equation
  • Knowledge of magnification as a ratio
  • Ability to construct scale drawings
  • Familiarity with basic optics concepts
NEXT STEPS
  • Study the thin lens equation in detail
  • Practice problems involving magnification ratios
  • Learn techniques for accurately drawing light rays through lenses
  • Explore real-life applications of lens equations in optics
USEFUL FOR

Students preparing for O level or GCSE physics, educators teaching optics, and anyone interested in mastering the principles of lens behavior and magnification.

Wasif Shah
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New poster has been reminded to post schoolwork-type questions in the HH fourms and to use the Template
Hey can anyone explain this question to me?
 

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Wasif Shah said:
Hey can anyone explain this question to me?

Have you tried applying the thin lens equation? Hint: what's the definition of magnification?
 
yeaah i tried using magnification=image/object ratio thing. But idk why in the solution they have taken the length of image as 50. I agree with taking 20 as the length of object but i don't get the taking 50 as the length of image.
 
The location of the image is deterimined by drawing three special light rays from the object through the lens.
How should such rays be drawn?
Have you tried constructing such a drawing by say using a scale of 1 cm in the drawing is 2 cm in real life?
 
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