Question: How do I say out loud the Callan-Symanzik Equation

[1equals1]

I'm looking for someone really clever to be able to tell me how to pronounce this equation if I were to say it out loud. I'm not particularly clued up when it comes to maths. (barely scraped a C in my GCSE) But I am definitely interested in its infinite (I'm sure someone will tell me about all the different infinities there are) capacity to explain all sorts of otherwise unexplainable things. Some help here would be greatly appreciated. (also I didn't know where to put this post, so I just went with other. Sorry if that was wrong) I don't exactly know how to type all of the characters in the right format, and I don't appear to be able to upload a picture of it, but it's called the Callan-Symanzik Equation.

 

[Greg]

Callan-Symanzik Equation (as given by Wikipedia):

$$\left[M\dfrac{\partial}{\partial M}+\beta(g)\dfrac{\partial}{\partial g}+n\gamma\right]G^{(n)}(x_1,x_2,\dots,x_n;M,g)=0$$

 

[1equals1]

Thank you for typing it on here. I'm still not quite sure how to pronounce any of these symbols in English?

 

[I like Serena]

Callan-Symanzik Equation (as given by Wikipedia):

$$\left[M\dfrac{\partial}{\partial M}+\beta(g)\dfrac{\partial}{\partial g}+n\gamma\right]G^{(n)}(x_1,x_2,\dots,x_n;M,g)=0$$

Thank you for typing it on here. I'm still not quite sure how to pronounce any of these symbols in English?

Hi 1equals1! Welcome to MHB! ;)$M$ is pronounced as /em/. :p
$\dfrac{\partial}{\partial M}$ is pronounced as /the partial derivative with respect to M/.
$\beta(g)$ is pronounced as /the beta function of g/.
$\gamma$ is pronounced as /gamma/.
$G^{(n)}(x_1,x_2,\dots,x_n;M,g)$ is pronouned as /the n-point correlation function G of $x_1$ up to $x_n$ with parameters M and g/.I don't know how one pronounces $Callan-Symanzik$.
Perhaps someone who is Russian or Polish or some such would know. :p