Question: Impulse and Force on a Vertical Window Struck by a Stream of Water

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Homework Help Overview

The problem involves a stream of water striking a vertical window, where the water stops upon impact. Participants are tasked with finding the impulse on the window over time and the force exerted, given specific quantities of water and its speed.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the momentum of the water and its change upon impact, exploring the relationship between impulse and time. There are attempts to break down the problem into components and clarify the implications of the given quantities.

Discussion Status

Some participants have provided guidance on calculating impulse and have prompted others to consider how it scales with time. There is a recognition of a discrepancy in units related to mass, which has led to further clarification and exploration of the problem.

Contextual Notes

Participants are navigating the distinction between grams and kilograms in their calculations, which has introduced some confusion regarding the expected answers.

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Homework Statement


Question: A stream of water from a hose is hitting a window. The window is vertical, the stream is horizontal, and the water stops when it hits. About 20cm(cubed), that is 20g, of water with speed 1.5 m/s strikes the window each second. Find a) the impulse on the window in time t and b) the force exerted on the window.


Homework Equations


I= delta p = mv -mu = Ft
f= delta p/t = mv-mu/t
s=ut +1/2 at (the last t is squared)

The Attempt at a Solution


well i originally tried to split this problem up into it vertical and horizontal components, saying that the water would follow a hyperbelar (i forget how to spell it) shape.

then i used the s=ut for the horizontal component (the rest of the equation isn't needed as the water doesn't accelerate horizontally and therefore is a 0 value) but then found that s and t arnt known.

i have a feeling it has something to do with the 20g of water with a force of 1.5m/s every second but i don't know what to do!

please help :)
 
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kateman said:
i have a feeling it has something to do with the 20g of water with a force of 1.5m/s every second but i don't know what to do!
Indeed.

What's the momentum of the water that hits the window every second? What's its change in momentum, thus impulse. If that's for 1 second, what would it be for t seconds?
 
delta p = mv-mu
-20 x 1.5 = -30

okay that's for 1 second,
but its the t seconds thing that gets me

and thanks for helping
 
kateman said:
delta p = mv-mu
-20 x 1.5 = -30
Good.
okay that's for 1 second,
but its the t seconds thing that gets me
Think about it. If the impulse is 30 kg-m/s for 1 sec, what would it be for 2 seconds? 3 seconds? t seconds? (It's easy.)
 
so 30t

haha right, i can't believe i didn't get that before :P

one problem; the answer in the back of the book is 0.03t N s
 
That's because Doc and you were talking about 30kg of water and the problem says 30g.
 
lol thanks dick
 
Dick said:
That's because Doc and you were talking about 30kg of water and the problem says 30g.
D'oh! :redface: Thanks, Dick.
 

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