Question on impulse, does it assume elastic collision?

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The discussion centers on the calculation of impulse and force in the context of a golf ball collision. Given a mass of 0.0459 kg and a velocity of 76.2 m/s, the impulse is calculated using the formula F(∆t), resulting in a force of 6998 N over a time of 0.0005 seconds. However, the presence of a coefficient of restitution of 0.65 indicates that the collision is not perfectly elastic, leading to a revised force calculation of 10766 N when accounting for energy loss during the collision.

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A problem I am working on for a project...
Force required to hit a golf ball 76.2 m/s
Does the impulse assume the collision is perfectly elastic?

I am doing a problem on golf...

mass of golf ball .0459 kg
velocity of ball is 76.2 m/s
time of interaction is .0005 seconds
coefficient of restitution is .65 (how efficient the collision is)



impulse - F(∆t)



F=6998 N
but would the force actually be 10766N (6998/.65) since the coefficient of restitution is .65?
 
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