Question on speed and velocity

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SUMMARY

The discussion focuses on calculating the depth of a well based on the time it takes for a stone to hit the water and the sound of the impact to travel back. The total time for the stone's descent (T1) and the sound's ascent (T2) is given as 4 seconds, with the velocity of sound specified at 350 m/s. By applying the equations of motion and sound propagation, participants can derive the depth of the well using the relationship T1 + T2 = 4 seconds.

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koshal303
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a stone is dropped in a well is heard to hit the water after 4 sec what will be the depth of the well if the velocity of sound is 350m/s ?


3. the time taken by stone to reach the water surface is T1 and the time taken by the sound to reach out is T2 now T1+T2 = 4 sec.
thats all i could do
 
Physics news on Phys.org
You only need to change 3.5 s in the other question with 4.0 s in your task :)

You are welcome to ask if you wonder how I did something there...
 

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