- #1
kwnmanu94
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How exactly did the terms in parenthesis of the equation (14) become (15)?
I don't even know what the Transport Theorem is about?
Question on the 3D Kinematics equation.
- Thread starter kwnmanu94
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The discussion centers on understanding the transition between two equations in 3D kinematics, specifically how the terms in parentheses of equation (14) relate to equation (15). Participants express confusion about the Transport Theorem, which is crucial for this transition. It is suggested that the theorem, which connects time derivatives in rotating coordinate systems, should be referenced in the textbook used. The relevant sections of the textbook, including diagrams and explanations of the Transport Theorem, are located on pages 4 and 5. Clarifying these concepts is essential for grasping the kinematic equations discussed.
How exactly did the terms in parenthesis of the equation (14) become (15)?
I don't even know what the Transport Theorem is about?
- #2
Filip Larsen
Gold Member
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What textbook is this? Since the text directly references Transport Theorem I would expect it to be described earlier. Perhaps look in the index or try compare with transport theorem where you can see it relates the coordinate-wise time derivative of a point coordinated by two different coordinate system that rotate relative to each other.
- #3
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https://ocw.mit.edu/courses/2-003sc...c8efae261114febe1f_MIT2_003SCF11Kinematic.pdf
Your diagram is on page 5.
The transport theorem is on page 4,
whose section is entitled
"2.2 Taking Derivatives using Angular Velocity and the Transport Theorem"
Your diagram is on page 5.
The transport theorem is on page 4,
whose section is entitled
"2.2 Taking Derivatives using Angular Velocity and the Transport Theorem"
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