- #1

ani4physics

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[H0 + lambda . V] [0> = [E0] [0>, where V is the perturbation hamiltonian.

Now we expand E0 as E0 = E0(0) + lambda . E0(1) + lambda^2. E0(2) +...

and [0> as [0> = [0>(0) + lambda. [0>(1) + lambda^2. [0>(2) + ...

Then we compare powers of lambda, left multiply with <0] to get the energy corrections and so on.

My question is, is the average energy of the atom E0 = E0(0) + E0(1) + E0(2) + ...

or is it [<0](0) + <0](1) + <0](2) + ...] [ H0 + lambda V] [[0>(0) + [0>(1) + [0>(2) + ...]

Which one is it? They give different result.