Question regarding distance traveled by a trebuchet

Click For Summary
SUMMARY

The discussion focuses on calculating the distance a water balloon launched by a trebuchet would travel, emphasizing the application of physics principles such as the Conservation of Energy. The user is designing a trebuchet to launch a 50-gram water balloon and is considering the conversion of potential energy from the counterweight into kinetic energy. Key factors include the launch angle of 45 degrees and the need to account for rotational kinetic energy in addition to translational kinetic energy. The conversation highlights the importance of understanding energy transfer and the effects of friction on the predicted distance.

PREREQUISITES
  • Understanding of Conservation of Energy principles
  • Basic knowledge of potential and kinetic energy
  • Familiarity with rotational kinetic energy equations
  • Concept of launch angles in projectile motion
NEXT STEPS
  • Study the equations for rotational kinetic energy
  • Research the effects of friction on projectile motion
  • Explore the physics of trebuchet mechanics
  • Learn about projectile motion calculations, including range and launch angles
USEFUL FOR

This discussion is beneficial for physics students, engineering students, and hobbyists interested in mechanics and projectile motion, particularly those designing catapults or trebuchets.

permapoop
Messages
10
Reaction score
0

Homework Statement


I need to find the distance traveled by a trebuchet. We were assigned to design and create one to launch a water balloon of roughly a mass of \approx50 grams. We are not allowed to test it, but must make a prediction of how far it would travel by using physics.


The Attempt at a Solution



I was trying to factor in rotational force and the transferring of potential to kinetic energy. The potential energy within the counterweight of the trebuchet would transfer the potential energy to kinetic energy so that the balloon can be launched. And I was thinking of using the Conservation of Energy to solve for the velocity and assume that the angle it launches at with the horizontal is 45 degrees.

Am I doing this correctly? Or is there a special solution on how to do it?
 
Physics news on Phys.org
The distance traveled by the trebuchet is generally zero, unless someone is moving it:biggrin:
In your case, you want to calculate the distance the water balloon travels.
Other than that, your plan seems reasonable. Of course, it ignores the energy wasted due to friction, but you should be able to get a reasonable estimate for how far the water balloon travels.
 
How would you factor in the rotational force in it though?
I'm still only a beginner in physics so I can't really figure it out.

I understand how to use the conservation of energy but I'm not sure if the rotation will affect it. Is it just mgh + 1/2mv2 = mgh + 1/2mv2?
 
Yes conservation of energy is a good way to look at this problem. Yes, rotatino plays a part in this. Do you know the equation for rotational kinetic energy? Your conservation of energy equation will include potential, translational kinetic, and rotational kinetic energies.
 

Similar threads

Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
2
Views
1K
Replies
23
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
6
Views
1K