Question related to power transmission

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Homework Help Overview

The discussion revolves around a physics problem related to power transmission, specifically involving a power station outputting 100kW at 20000V connected to a factory via cables with a resistance of 5.0 Ω. The original poster attempts to calculate the current flowing through the cables and questions the applicability of Ohm's law in this context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use Ohm's law (V=IR) to find the current but questions why this approach seems incorrect in this scenario. Other participants clarify that the potential difference needed for Ohm's law is not defined between the relevant points, leading to confusion about the application of the law.

Discussion Status

Participants are exploring the relationship between voltage, current, and resistance in the context of the problem. Some have provided clarifications regarding the use of Ohm's law and the importance of knowing the potential difference across specific points. There is an acknowledgment of the complexity involved in applying these concepts to the given situation.

Contextual Notes

There is a discussion about the effective resistance and potential difference across the cable and factory, indicating that additional information about the factory's resistance would be necessary for a complete analysis. The original poster expresses a lack of confidence in their understanding of the physics involved.

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First of all I'd like to say hello. Secondly, my Physics is not very exceptional, so please don't mock me if I ask sth very dumb. :)

Homework Statement


A power station giving an output power of 100kW at 20000V is connected by cables to a factory.
If the resistance of the cables is 5.0 Ω, calculate:
(a) the current flowing in the cables,


Homework Equations


P=VI


The Attempt at a Solution


I tried solving this using "V=IR". Here's my attempt.

V=IR
20000 = I x 5
I = 20000/5 = 4000 A.

The actual solution given is:

Since P (Output) = IV where I is the current in the cables

I=P/V
= 100kW/20000
=...= 5A

I just need to know why we can't use "V=IR". My guess is it has to sth about a.c. or d.c.
 
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Hi DarkStalker,

A more precise statement of Ohm's law would be:

<br /> \Delta V = I R<br />

so if you want to know the current flowing from one point to another, you need the resistance between those points and the voltage difference between those points. Can you see why the 5 ohms and the 20000 V don't go together in Ohm's law in this problem?
 
So what you're trying to say is that since we don't the potential difference between any two points on the wire, Ohm's law cannot be applied, right?
And if we knew the p.d., it would've been something like very lower than 20000?
 
DarkStalker said:
So what you're trying to say is that since we don't the potential difference between any two points on the wire, Ohm's law cannot be applied, right?
And if we knew the p.d., it would've been something like very lower than 20000?

Exactly right; the 20000 V potential difference is across the cable and the factory. So, if for example, they gave you the "effective resistance" of the factory, you could combine it in series with the 5 ohms from the cable and then follow your procedure.

The solution from the book works, because it uses the total power (of cable and factory) and the total potential difference (across cable and factory).


Now that you know the current, you could actually use your approach to find what the potential difference across the cable is.
 
Because the voltage is varying with the current throughout the /entire/ cable (because you have a 5 ohm resistance all the way to the factory), you cannot use ohm's law.

edit: a bit too late!
 
Thanks a lot, all of you. :)
BryanP said:
edit: a bit too late!
Not really. I'm so bad at physics that any different way of explaining helps.
 

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