Transmission cable problem involving power loss

  • Thread starter Thread starter hendrix7
  • Start date Start date
  • Tags Tags
    Power loss
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 1K views
hendrix7
Messages
36
Reaction score
8
Homework Statement
A transmission cable transmits electricity at 250A and 400kV and a resistance of 3 ohms. What is the power loss?
Relevant Equations
P = I^2R
V = IR
Using P = I2R
2502 x 3 = 187.5kW
Now, I'm pretty sure that this is correct but my question is how does V = IR fit in with this? So, I = 250 and R = 3 so V must be 750, but what does this 750 volts represent? A voltage drop between two points on the transmission cable? If so, where are the two points on the transmission cable that correspond to this potential difference? Am I missing something here? This is pretty new to me so I would much appreciate it if someone could put me straight here or clarify for me.
 
Physics news on Phys.org
The input voltage of 400kV is reduced slightly at the far end by the resistive losses. The 750V drop is for the 2-way wire voltage drop from source to destination. You should get the same power loss if you do either calculation, using ##I^2R## loss or ##\frac{V^2}{R}## loss.
 
Reply
  • Like
Likes   Reactions: hendrix7
berkeman said:
The input voltage of 400kV is reduced slightly at the far end by the resistive losses. The 750V drop is for the 2-way wire voltage drop from source to destination. You should get the same power loss if you do either calculation, using ##I^2R## loss or ##\frac{V^2}{R}## loss.
Thank you, berkeman, that seems clear to me now. I really appreciate that.
 
Reply
  • Like
Likes   Reactions: berkeman