I Questions about Franck-Condon principle

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The Franck-Condon principle explains that vibrational transitions are more likely between states with similar wavefunctions, but a photon must have sufficient energy to facilitate transitions between specific vibrational levels. If a photon has enough energy for an electronic transition, it is not mandatory for the molecule to undergo a vibrational transition; it can transition between electronic states while remaining in the same vibrational level. The potential energy diagram indicates that an excited electronic state is represented higher than the ground state, reflecting the energy of the excited electrons. If multiple electrons are excited, the potential energy levels would be drawn higher for each additional excited electron. Clarifying these concepts can enhance understanding of molecular transitions and the Franck-Condon principle.
Salmone
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I have some questions on Franck Condon principle:

1. The principle states that if a molecule absorbs a photon of the appropriate energy, we could have both electronic and vibrational transitions and that is more likely to have a vibrational transition between states that have two "similar" wavefunctions. The first question is:
It is ok to me that it is more likely to have a vibrational transition between states that have two "similar" wavefunctions but of course if we see a transition between ##\nu=0## state and ##\nu'=5## state means that the absorbed photon had at least the energy separating ##\nu''=0## and ##\nu'=6##, right? With reference to the image, the "blue arrow transition" is more lilely to happen but we need a photon with the right energy, more or equal to the "lenght" of the arrow, right?

2. If the energy of the incoming photon is enough for that transition, is it mandatory for the molecule to also have a vibrational transition or it can jump just from electronic G.S. to electronic first excited state remaining on the same vibrational level?

3. Again with reference to the image, the potential drawn higher refers to an excited electronic state, if we are talking about molecules, what do we precisely mean by that? If just one electron of the electronic clouds is excited by a photon, the new arrangement of the molecule need to be drawn higher than the ground state in which all electrons were in their ground states? And, if two photons are excited, the new potential must be drawn as a different one much higher? Same if three electrons are excited or two electrons are excited to second excited state or third excited state?

800px-Franck_Condon_Diagram.svg.png
 
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Doubts meaning you do not think it works like that or that you don't understand that principle?
 
malawi_glenn said:
Doubts meaning you do not think it works like that or that you don't understand that principle?
I don't understand the points I've written
 
Salmone said:
I don't understand the points I've written
You have questions. You should write questions instead of 'doubts'.
 
We often see discussions about what QM and QFT mean, but hardly anything on just how fundamental they are to much of physics. To rectify that, see the following; https://www.cambridge.org/engage/api-gateway/coe/assets/orp/resource/item/66a6a6005101a2ffa86cdd48/original/a-derivation-of-maxwell-s-equations-from-first-principles.pdf 'Somewhat magically, if one then applies local gauge invariance to the Dirac Lagrangian, a field appears, and from this field it is possible to derive Maxwell’s...

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